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Question
In quadrilateral ABCD, the diagonals AC and BD intersect each other at point O. If AO = 2CO and BO = 2DO; show that: OA × OD = OB × OC.
Solution
Since AO = 2CO and BO = 2DO,
`(AO)/(CO) = 2/1 = (BO)/(DO)`
So, OA × OD = OB × OC
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