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Question
In the given figure, ∠ABC = ∠DCB = 90° AB = 6, DC = 8 then `("A(Δ ABC)")/("A(Δ DCB)")` = ?
Solution
Given:
∠ABC = ∠DCB = 90°
AB = 6
DC = 8
Now,
`("A(Δ ABC)")/("A(Δ DCB)") = (1/2 xx "AB" xx "BC")/(1/2 xx "DC" xx "BC")`
= `6/8`
= `3/4`
∴ `("A(Δ ABC)")/("A(Δ DCB)") = 3/4`
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