English

In the Given Figure, Ps = 2rs. M is the Midpoint of Qr. If Tr || Mn || Qp, Then Prove That:St = 1 3 Ls - Mathematics

Advertisements
Advertisements

Question

In the given figure, PS = 3RS. M is the midpoint of QR. If TR || MN || QP, then prove that:

ST = `(1)/(3)"LS"`

Sum

Solution

Proof :
In ΔPQR,
Since M is the mid-point of QR, and MN || QP, N is the mid-point of PR.
⇒ PN = PR
Given PS = 3RS
⇒ PS = RS = PN + NR + RS
But, PS = PN + NR + Rs
⇒ PN = PR = Rs
⇒R is the mid-point of SN
RT || MN
⇒ T is the mid-point of SM  ....(i)
Also, N is the mid-point of PR and MN || LP
⇒ M is the mid-point of LT   ....(ii)
So, from (i) and (ii),
LM = MT = ST

⇒ ST = `(1)/(3)"LS"`.

shaalaa.com
  Is there an error in this question or solution?
Chapter 15: Mid-point and Intercept Theorems - Exercise 15.2

APPEARS IN

Frank Mathematics [English] Class 9 ICSE
Chapter 15 Mid-point and Intercept Theorems
Exercise 15.2 | Q 8.1

RELATED QUESTIONS

ABCD is a trapezium in which AB || DC, BD is a diagonal and E is the mid-point of AD. A line is drawn through E parallel to AB intersecting BC at F (see the given figure). Show that F is the mid-point of BC.


In a ΔABC, E and F are the mid-points of AC and AB respectively. The altitude AP to BC
intersects FE at Q. Prove that AQ = QP.


In below Fig, ABCD is a parallelogram in which P is the mid-point of DC and Q is a point on AC such that CQ = `1/4` AC. If PQ produced meets BC at R, prove that R is a mid-point of BC.


BM and CN are perpendiculars to a line passing through the vertex A of a triangle ABC. If
L is the mid-point of BC, prove that LM = LN.


In trapezium ABCD, sides AB and DC are parallel to each other. E is mid-point of AD and F is mid-point of BC.
Prove that: AB + DC = 2EF.


In the given figure, AD and CE are medians and DF // CE.
Prove that: FB = `1/4` AB.


In triangle ABC ; D and E are mid-points of the sides AB and AC respectively. Through E, a straight line is drawn parallel to AB to meet BC at F.
Prove that BDEF is a parallelogram. If AB = 16 cm, AC = 12 cm and BC = 18 cm,
find the perimeter of the parallelogram BDEF.


The diagonals AC and BD of a quadrilateral ABCD intersect at right angles. Prove that the quadrilateral formed by joining the midpoints of quadrilateral ABCD is a rectangle.


P and Q are the mid-points of the opposite sides AB and CD of a parallelogram ABCD. AQ intersects DP at S and BQ intersects CP at R. Show that PRQS is a parallelogram.


D, E and F are respectively the mid-points of the sides AB, BC and CA of a triangle ABC. Prove that by joining these mid-points D, E and F, the triangles ABC is divided into four congruent triangles.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×