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Question
In the given figure, RS is a diameter of the circle. NM is parallel to RS and ∠MRS = 29°. Calculate : ∠RNM
Solution
Join RN and MS.
∴ ∠RMS = 90°
(Angle in a semicircle is a right angle)
∴ ∠RSM = 90° – 29° = 61°
(By angle sum property of triangle RMS)
∴ ∠RNM = 180° ∠RSM = 180° – 61° = 119°
(Pair of opposite angles in a cyclic quadrilateral are supplementary)
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