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Question
In the following figure, AD is the diameter of the circle with centre O. Chords AB, BC and CD are equal. If ∠DEF = 110°, calculate: ∠AEF
Solution
Join AE, OB and OC
∵ AOD is the diameter,
∴ ∠AED = 90° ...[Angle in a semi-circle]
But ∠DEF = 110° ...[Given]
∴ ∠AEF = ∠DEF – ∠AED
= 110° – 90°
= 20°
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