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Let R Be a Relation Defined on the Set of Natural Numbers N as R = {(X, Y) : X, Y ∈ N, 2x + Y = 41} Find the Domain and Range of R. Also, Verify Whether R is (I) Reflexive, (Ii) Symmetric (Iii) Transi - Mathematics

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Question

Let R be a relation defined on the set of natural numbers N as
R = {(xy) : x N, 2x + y = 41}
Find the domain and range of R. Also, verify whether R is (i) reflexive, (ii) symmetric (iii) transitive.

Sum

Solution

Domain of R is the values of x and range of R is the values of y that together should satisfy 2x+y = 41.
So,
Domain of R = {1, 2, 3, 4, ... , 20}
Range of R = {1, 3, 5, ... , 37, 39}

Reflexivity : Let x be an arbitrary element of R. Then,

x ∈ R

⇒ 2x+x = 41 cannot be true.

⇒ (x, x) ∉ R

So, R is not reflexive.

Symmetry :

Let (x,y) ∈ R.Then,

2x+y = 41

⇒ 2y+x = 41 

⇒(y, x)∉R

So, R is not symmetric.

Transitivity :

Let (x, y) and (y, z)∈R

⇒ 2x+y = 41 and 2y + z = 41

⇒ 2x+z = 2x+ 41− 2y  41−y−2y = 41−3y

⇒ (x, z) ∉ R

Thus, R is not transitive.

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Chapter 1: Relations - Exercise 1.1 [Page 11]

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RD Sharma Mathematics [English] Class 12
Chapter 1 Relations
Exercise 1.1 | Q 10 | Page 11

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