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Question
\[\lim_{x \to } \frac{1 - \cos 2x}{x} is\]
Options
(a) 0
(b) 1
(c) 2
(d) 4
Solution
\[\lim_{x \to 0} \frac{1 - \cos 2x}{x}\]
\[ = \lim_{x \to 0} \frac{2 \sin^2 x}{x}\]
\[ = \lim_{x \to 0} 2x \times \frac{\sin^2 x}{x^2}\]
\[ \Rightarrow 0\]
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