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Show that Xcosecx = 1 + X 2 6 + 7 X 4 360 + ... ... - Applied Mathematics 1

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Question

Show that xcosecx = `1+x^2/6+(7x^4)/360+......` 

Sum

Solution

LHS = xcosecx 

=` x/sinx`

= `x/(x-x^3/(3!)+x^5/(5!)-x^6/(7!)+..........`

= `x/(x(1- x^2/(3!)+x^4/(5!)-x^6/(7!)+..........)` 

=`[(1-(x^2/(3!)-x^4/(5!)+x^6/(7!)))]^(-1)`

=`1+(x^2/(3!)-x^4/(5!)+x^6/(7!)-..........)+(x^2/(3!)-x^4/(5!)+x^6/(7!)-.........)^2+.......{โˆต(1-y)^1=1+y+y^2+y^3+.............}`

=`1+x^2/3!-x^4/5!+(x^2/3!)+........`

=`1+x^2/6+(7x^4)/360+........`

∴ xcosecx =` 1+x^2/6+(7x^4)/360+........`

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Expansion of ๐‘’^๐‘ฅ , sin(x), cos(x), tan(x), sinh(x), cosh(x), tanh(x), log(1+x), ๐‘ ๐‘–๐‘›โˆ’1 (๐‘ฅ),๐‘๐‘œ๐‘ โˆ’1 (๐‘ฅ),๐‘ก๐‘Ž๐‘›โˆ’1 (๐‘ฅ)
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2017-2018 (December) CBCGS
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