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Question
Solve the following system of equation in R.
x + 5 > 2(x + 1), 2 − x < 3 (x + 2)
Solution
x + 5 > 2(x + 1) and 2 − x < 3(x + 2)
x + 5 > 2x + 2 2 − x < 3x + 6
5 − 2 > 2x − x 2 − 6 < 3x + x
3 > x 4x > −4
x < 3 and x > −1
Hence, x ∈ (−1, 3) R
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