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The Angles A, B, C and D of a Trapezium Abcd Are in the Ratio 3 : 4 : 5 : 6. Le. ∠A : ∠B : ∠C : ∠D = 3:4: 5 : 6. - Mathematics

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Question

The angles A, B, C and D of a trapezium ABCD are in the ratio 3: 4: 5: 6. Le. ∠A : ∠B : ∠C : ∠D = 3:4: 5 : 6. Find all the angles of the trapezium. Also, name the two sides of this trapezium which are parallel to each other. Give reason for your answer.

Sum

Solution

As the trapezium ABCD is a quadrilateral,

∴ Sum of its interior angles = 360°

⇒ ∠A + ∠B + ∠C + ∠D = 360°

⇒ 3x + 4x + 5x + 6x = 360°

⇒ 18x = 360°

⇒ x = `360^circ/18 = 20°`

∴ ∠A = 3x = 3 × 20° = 60°

and ∠B = 4x = 4 × 20° = 80°

and ∠C = 5x = 5 × 20° = 100°

and ∠D = 6x = 6 × 20° = 120°

AB is parallel to DC.

∵ ∠A + ∠D = 180°

∠A and ∠D are co-interior angles whose sum = 180°

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Chapter 27: Quadrilateral - Exercise 27 (B)

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Selina Mathematics [English] Class 6
Chapter 27 Quadrilateral
Exercise 27 (B) | Q 3

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