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The areas of two similar triangles are in respectively 9 cm2 and 16 cm2. The ratio of their corresponding sides is ______. - Mathematics

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Question

The areas of two similar triangles are in respectively 9 cm2 and 16 cm2. The ratio of their corresponding sides is ______.

Options

  •  3 : 4

  • 4 : 3

  •  2 : 3

  • 4 : 5

MCQ
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Solution

The areas of two similar triangles are in respectively 9 cm2 and 16 cm2. The ratio of their corresponding sides is  3 : 4.

Explanation:

Given: Areas of two similar triangles are 9cm2 and 16cm2.

To find: Ratio of their corresponding sides.

We know that the ratio of areas of two similar triangles is equal to the ratio of squares of their corresponding sides.

`\text{ar(tringle 1)}/\text{ar(tringle 2)}=(\text{side1}/\text{side2})^2`

`9/16 = (\text{side1}/\text{side2})^2`

Taking square root on both sides, we get

\[\frac{\text{side1}}{\text{side2}} = \frac{3}{4}\]

So, the ratio of their corresponding sides is 3 : 4.

Hence the correct answer is `a`

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Chapter 7: Triangles - Exercise 7.10 [Page 131]

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RD Sharma Mathematics [English] Class 10
Chapter 7 Triangles
Exercise 7.10 | Q 2 | Page 131

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