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Question
The degree of the differential equation `("d"^2"y")/("dx"^2) + 3("dy"/"dx")^2 = "x"^2 (("d"^2"y")/("dx"^2))^2` is:
Options
1
2
3
4
Solution
2
Explanation:
Given differential equation is
`("d"^2"y")/("dx"^2) + 3("dy"/"dx")^2 = "x"^2 (("d"^2"y")/("dx"^2))^2`
The degree of a differential equation is the degree of the highest order occurring in it.
So, the order of the differential equation is 2 and the degree of the differential equation is also 2.
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