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Question
Two circles touch externally. The sum of their areas is 130π sq. cm and the distance between their centers is 14 cm. Find the radii of the circles.
Solution
Let the radii of two circles be r1 and r2 respectively.
Sum of the areas of two circles = 130π sq. cm
⇒ πr12 + πr22 = 130π
⇒ r12 + r22 = 130 ….(i)
Also, distance between two radii = 14 cm
⇒ r1 + r2 = 14
⇒ r1 = (14 - r2)
Substituting the value of r1 in (i), we get
(14 - r2)2 + r22 = 130
⇒ 196 - 28r2 + r22 + r22 = 130
⇒ 2r22 - 28r2 + 66 = 0
⇒ r22 - 14r2 + 33 = 0
⇒ r22 - 11r2 - 3r2 + 33 = 0
⇒ r2 (r2 - 11) - 3 (r2 - 11) = 0
⇒ (r2 - 11) (r2 - 3) = 0
⇒ r2 = 11 or r2 = 3
⇒ r1 = 14 - 11 = 3 or r1 = 14 - 3 = 11
Thus, the radii of two circles are 11 cm and 3 cm respectively.
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