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Question
With vertices A, B and C of ΔABC as centres, arcs are drawn with radii 14 cm and the three portions of the triangle so obtained are removed. Find the total area removed from the triangle.
Solution
Total area removed = `(∠A)/360 πr^2 + (∠B)/360 πr^2 + (∠C)/360 πr^2`
= `(∠A + ∠B + ∠C)/360 πr^2`
= `180/360 πr^2`
= `180/360 xx 22/7 xx (14)^2`
= 308 cm2
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