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3(sinx – cosx)4 + 6(sinx + cosx)2 + 4(sin6x + cos6x) = ______. - Mathematics

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प्रश्न

3(sinx – cosx)4 + 6(sinx + cosx)2 + 4(sin6x + cos6x) = ______.

रिक्त स्थान भरें

उत्तर

3(sinx – cosx)4 + 6(sinx + cosx)2 + 4(sin6x + cos6x) = 13.

Explanation:

Given expression is 3(sinx – cosx)4 + 6(sinx + cosx)2 + 4(sin6x + cos6x) 

= 3[sin2x + cos2x – 2 sinx cosx]2 + 6(sin2x + cos2x + 2sinx cosx) + 4[(sin2x)3 + (cos2x)3]

= 3[1 – 2sinx cosx]2 + 6(1 + 2sinx cosx) + 4[(sin2x + cos2x)3 – 3sin2x cos2x (sin2x + cos2x)]

= 3[1 + 4sin2x cos2x – 4sinx cosx] + 6(1 + 2 sinx cosx) + 4[1 – 3sin2x cos2x]

= 3 + 12sin2x cos2x – 12sinx cosx + 6 + 12sinx cosx + 4 – 12sin2x cos2x

= 3 + 6 + 4

= 13

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अध्याय 3: Trigonometric Functions - Exercise [पृष्ठ ५९]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
अध्याय 3 Trigonometric Functions
Exercise | Q 65 | पृष्ठ ५९

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