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Prove the following: sin 2x + 2sin 4x + sin 6x = 4cos2 x sin 4x - Mathematics

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प्रश्न

Prove the following:

sin 2x + 2sin 4x + sin 6x = 4cos2 x sin 4x

योग

उत्तर

L.H.S. = sin 2x + 2 sin 4x + sin 6x

= [sin 2x + sin 6x] + 2 sin 4x

= `2sin ((6x + 2x)/2)cos ((6x - 2x)/2) + 2sin 4x`

`[∵ sin A + B = 2 sin ((A+ B)/2) cos ((A - B)/2)]`

= 2 sin 4x cos (– 2x) + 2 sin 4x

= 2 sin 4x cos 2x + 2 sin 4x

= 2 sin 4x (cos 2x + 1)

= 2 sin 4x (2 cos2 x – 1 + 1)

= 2 sin 4x (2 cos2 x)

= 4cos2 x sin 4x

= R.H.S.

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अध्याय 3: Trigonometric Functions - Exercise 3.3 [पृष्ठ ७३]

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एनसीईआरटी Mathematics [English] Class 11
अध्याय 3 Trigonometric Functions
Exercise 3.3 | Q 14 | पृष्ठ ७३

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