हिंदी

A Particle Executes S.H.M. with a Period of 10 Seconds. Find the Time in Which Its Potential Energy Will Be Half of Its Total Energy. - Physics

Advertisements
Advertisements

प्रश्न

A particle executes S.H.M. with a period of 10 seconds. Find the time in which its potential energy will be half of its total energy.

उत्तर

Given: T = 10 s

P. E = `1/2 (T.E)`

To find: Time (t)

∴ t = 1.25 s

The time in which the potential energy will be half of total energy is 1.25 s.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2015-2016 (July)

APPEARS IN

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

A body of mass 1 kg is made to oscillate on a spring of force constant 16 N/m. Calculate:

a) Angular frequency

b) frequency of vibration.


Hence obtain the expression for acceleration, velocity and displacement of a particle performing linear S.H.M.


A particle executing simple harmonic motion comes to rest at the extreme positions. Is the resultant force on the particle zero at these positions according to Newton's first law?


A particle executes simple harmonic motion. If you are told that its velocity at this instant is zero, can you say what is its displacement? If you are told that its velocity at this instant is maximum, can you say what is its displacement?


A small creature moves with constant speed in a vertical circle on a bright day. Does its shadow formed by the sun on a horizontal plane move in a sample harmonic motion?


The energy of system in simple harmonic motion is given by \[E = \frac{1}{2}m \omega^2 A^2 .\] Which of the following two statements is more appropriate?
(A) The energy is increased because the amplitude is increased.
(B) The amplitude is increased because the energy is increased.


Can a pendulum clock be used in an earth-satellite?


The displacement of a particle is given by \[\overrightarrow{r} = A\left( \overrightarrow{i} \cos\omega t + \overrightarrow{j} \sin\omega t \right) .\] The motion of the particle is

 

A particle moves on the X-axis according to the equation x = A + B sin ωt. The motion is simple harmonic with amplitude


The average energy in one time period in simple harmonic motion is


An object is released from rest. The time it takes to fall through a distance h and the speed of the object as it falls through this distance are measured with a pendulum clock. The entire apparatus is taken on the moon and the experiment is repeated
(a) the measured times are same
(b) the measured speeds are same
(c) the actual times in the fall are equal
(d) the actual speeds are equal


A particle executes simple harmonic motion with an amplitude of 10 cm and time period 6 s. At t = 0 it is at position x = 5 cm going towards positive x-direction. Write the equation for the displacement x at time t. Find the magnitude of the acceleration of the particle at t = 4 s.


The angle made by the string of a simple pendulum with the vertical depends on time as \[\theta = \frac{\pi}{90}  \sin  \left[ \left( \pi  s^{- 1} \right)t \right]\] .Find the length of the pendulum if g = π2 m2.


A simple pendulum of length l is suspended through the ceiling of an elevator. Find the time period of small oscillations if the elevator (a) is going up with and acceleration a0(b) is going down with an acceleration a0 and (c) is moving with a uniform velocity.


A closed circular wire hung on a nail in a wall undergoes small oscillations of amplitude 20 and time period 2 s. Find (a) the radius of the circular wire, (b) the speed of the particle farthest away from the point of suspension as it goes through its mean position, (c) the acceleration of this particle as it goes through its mean position and (d) the acceleration of this particle when it is at an extreme position. Take g = π2 m/s2.


A uniform disc of mass m and radius r is suspended through a wire attached to its centre. If the time period of the torsional oscillations be T, what is the torsional constant of the wire?


A particle is subjected to two simple harmonic motions of same time period in the same direction. The amplitude of the first motion is 3.0 cm and that of the second is 4.0 cm. Find the resultant amplitude if the phase difference between the motions is (a) 0°, (b) 60°, (c) 90°.


Three simple harmonic motions of equal amplitude A and equal time periods in the same direction combine. The phase of the second motion is 60° ahead of the first and the phase of the third motion is 60° ahead of the second. Find the amplitude of the resultant motion.


In a simple harmonic oscillation, the acceleration against displacement for one complete oscillation will be __________.


The length of a second’s pendulum on the surface of the Earth is 0.9 m. The length of the same pendulum on the surface of planet X such that the acceleration of the planet X is n times greater than the Earth is


A simple pendulum has a time period T1. When its point of suspension is moved vertically upwards according to as y = kt2, where y is the vertical distance covered and k = 1 ms−2, its time period becomes T2. Then, T `"T"_1^2/"T"_2^2` is (g = 10 ms−2)


Define the time period of simple harmonic motion.


What is an epoch?


Write short notes on two springs connected in parallel.


Consider a simple pendulum of length l = 0.9 m which is properly placed on a trolley rolling down on a inclined plane which is at θ = 45° with the horizontal. Assuming that the inclined plane is frictionless, calculate the time period of oscillation of the simple pendulum.


The displacement of a particle is represented by the equation `y = 3 cos (pi/4 - 2ωt)`. The motion of the particle is ______.


Motion of a ball bearing inside a smooth curved bowl, when released from a point slightly above the lower point is ______.

  1. simple harmonic motion.
  2. non-periodic motion.
  3. periodic motion.
  4. periodic but not S.H.M.

Displacement vs. time curve for a particle executing S.H.M. is shown in figure. Choose the correct statements.

  1. Phase of the oscillator is same at t = 0 s and t = 2s.
  2. Phase of the oscillator is same at t = 2 s and t = 6s.
  3. Phase of the oscillator is same at t = 1 s and t = 7s.
  4. Phase of the oscillator is same at t = 1 s and t = 5s.

The velocities of a particle in SHM at positions x1 and x2 are v1 and v2 respectively, its time period will be ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×