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A point P is 26 cm away from O of circle and the length PT of the tangent drawn from P to the circle is 10 cm. Find the radius of the circle.
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Given OP = 26 cm
PT = length of tangent = 10cm
radius = OT = ?
At point of contact, radius and tangent are perpendicular ∠OTP = 90°, ΔOTP is right
angled triangle.
By Pythagoras theorem, ЁЭСВЁЭСГ2 = ЁЭСВЁЭСЗ2 + ЁЭСГЁЭСЗ2
262 = ЁЭСВЁЭСЗ2 + 102
ЁЭСВЁЭСЗЁЭСШ =` (sqrt(676 − 100))`ЁЭСШ
ЁЭСВЁЭСЗ = `sqrt(576)`
= 24 cm
OT = length of tangent = 24 cm
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