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Determine n if 2nC3:nC3=12:1 - Mathematics

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प्रश्न

Determine n if  `""^(2n)C_3 : ""^nC_3 = 12 : 1`

योग

उत्तर

`(""^(2n)C_3)/(""^nC_3) = 12/1`

⇒ `((2n)!)/(3!(2n - 3)!) xx (3!(n - 3)!)/(n!) = 12/1`

⇒ `((2n)(2n - 1)(2n - 2)(2n - 3)!)/((2n - 3)!) xx ((n - 3)!)/(n(n - 1)(n - 2)(n - 3)!) = 12`

⇒ `(2(2n - 1)(2n - 2))/((n - 1)(n - 2)) = 12`

⇒ `(4(2n - 1)(n - 1))/((n - 1)(n - 2)) = 12`

⇒ `((2n - 1))/((n - 2)) = 3`

⇒ 2n - 1 = 3 (n - 2)

⇒ 2n - 1 = 3n - 6

⇒ 3n - 2n = -1 + 6

⇒ n = 5

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अध्याय 7: Permutations and Combinations - Exercise 7.4 [पृष्ठ १५३]

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एनसीईआरटी Mathematics [English] Class 11
अध्याय 7 Permutations and Combinations
Exercise 7.4 | Q 2.1 | पृष्ठ १५३

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