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प्रश्न
Differentiate
log (1 + x2) w.r.t. tan-1 (x)
उत्तर
Let u = log(1 + x2) and v = tan-1 (x)
Deffrentiating both sides with respect to x.
`(du)/dx = 1/(1 + x^2) . 2x, (dv)/dx = 1/(1 + x^2)`
`(du)/(dv) = ((du)/dx)/((dv)/dx) = ((2x/1 + x^2))/((1/(1 + x^2))`
`(du)/(dv) = 2x`
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