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प्रश्न
Evaluate the following:
`cot^-1{2cos(sin^-1 sqrt3/2)}`
उत्तर
`cot^-1{2cos(sin^-1 sqrt3/2)}=cot^-1{2cos[sin^-1(sin pi/3)]}`
`=cot^-1(2cos pi/3)`
`=cot^-1(2xx1/2)`
`=cot^-1(1)`
`=cot^-1(tan pi/4)`
`=pi/4`
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