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प्रश्न
Find the following product:
−11a(3a + 2b)
उत्तर
To find the product, we will use distributive law as follows:
\[- 11a\left( 3a + 2b \right)\]
\[ = \left( - 11a \right) \times 3a + \left( - 11a \right) \times 2b\]
\[ = \left( - 11 \times 3 \right) \times \left( a \times a \right) + \left( - 11 \times 2 \right) \times \left( a \times b \right)\]
\[ = \left( - 33 \right) \times \left( a^{1 + 1} \right) + \left( - 22 \right) \times \left( a \times b \right)\]
\[ = - 33 a^2 - 22ab\]
Thus, the answer is \[- 33 a^2 - 22ab\].
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