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Find the length of each side of a rhombus whose diagonals are 24cm and 10cm long.
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Suppose ABCD is a rhombus.
We know that the diagonals of a rhombus perpendicularly bisect each other.
∴ ∠ЁЭР┤ЁЭСВЁЭР╡ = `90^0` , ЁЭР┤ЁЭСВ = 12 ЁЭСРЁЭСЪ ЁЭСОЁЭСЫЁЭСС ЁЭР╡ЁЭСВ = 5 ЁЭСРЁЭСЪ
Now, In right triangle AOB
By using Pythagoras theorem we have
`AB^2=AO^2+BO^2`
`=12^2+5^2`
`=144+25`
`=169`
∴` AB^2=169`
⇒ AB=13 cm
Since, all the sides of a rhombus are equal.
Hence, AB = BC = CD = DA = 13 cm
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