Advertisements
Advertisements
प्रश्न
Find the inverse of the following matrix by the adjoint method.
`[(-1,5),(-3,2)]`
उत्तर
Let A = `[(-1,5),(-3,2)]`
∴ |A| = `|(-1,5),(-3,2)|` = − 2 + 15 = 13 `≠` 0
∴ A−1 exists.
First we have to find the co-factor matrix
= [Aij]2×2′ where Aij = (− 1)i+jMij
Now, A11 = (− 1)1+1M11 = 2
A12 = (− 1)1+2M12 = − (− 3) = 3
A21 = (− 1)2+1M21 = − 5
A22 = (− 1)2+2M22 = − 1
Hence, the co-factor matrix
= `[("A"_11,"A"_12),("A"_21,"A"_22)]` = `[(2,3),(-5,-1)]`
∴ adj A = `[(2,-5),(3,-1)]`
∴ A−1 = `1/|"A"|` (adj A) = `1/13[(2,-5),(3,-1)]`
APPEARS IN
संबंधित प्रश्न
The sum of three numbers is 6. If we multiply the third number by 3 and add it to the second number we get 11. By adding first and third numbers we get a number, which is double than the second number. Use this information and find a system of linear equations. Find these three numbers using matrices.
Find the adjoint of the following matrix.
`[(2,-3),(3,5)]`
Choose the correct answer from the given alternatives in the following question:
If A = `[("cos"alpha, - "sin"alpha,0),("sin"alpha,"cos"alpha,0),(0,0,1)]` where α ∈ R, then [F(α)]-1 is
Choose the correct answer from the given alternatives in the following question:
The inverse of A = `[(0,1,0),(1,0,0),(0,0,1)]` is
Find matrix X, if AX = B, where A = `[(1, 2, 3),(-1, 1, 2),(1, 2, 4)] "and B" = [(1),(2),(3)]`.
Adjoint of `[(2, -3),(4, -6)]` is _______
If A = `[(1, 2),(-3, -1)], "B" = [(-1, 0),(1, 5)]`, then AB =
Fill in the blank :
If A = [aij]mxm is a non-singular matrix, then A–1 = `(1)/(......)` adj(A).
State whether the following is True or False :
A = `[(2, 1),(10, 5)]` is invertible matrix.
State whether the following is True or False :
Singleton matrix is only row matrix.
Check whether the following matrices are invertible or not:
`[(1, 2, 3),(2, 4, 5),(2, 4, 6)]`
The solution (x, y, z) of the equation `[(1, 0, 1),(-1, 1, 0),(0, -1, 1)] [(x),(y),(z)] = [(1),(1),(2)]` is (x, y, z) =
If A = `[(4, -1),(-1, "k")]` such that A2 − 6A + 7I = 0, then K = ______
`cos theta [(cos theta, sin theta),(-sin theta, cos theta)] + sin theta [(sin theta, - cos theta),(cos theta, sin theta)]` = ______
If A = `[(4, 5),(2, 5)]`, then |(2A)−1| = ______
If A = `[(3, 0, 0),(0, 3, 0),(0, 0, 3)]`, then |A| |adj A| = ______
For an invertible matrix A, if A . (adj A) = `[(10, 0),(0, 10)]`, then find the value of |A|.
If A(α) = `[(cos alpha, sin alpha),(-sin alpha, cos alpha)]` then prove that A2(α) = A(2α)
A + I = `[(3, -2),(4, 1)]` then find the value of (A + I)(A − I)
If A = `[(0, 3, 3),(-3, 0, -4),(-3, 4, 0)]` and B = `[(x),(y),(z)]`, find the matrix B'(AB)
Find the adjoint of matrix A = `[(2, 0, -1),(3, 1, 2),(-1, 1, 2)]`
Choose the correct alternative:
If A is a non singular matrix of order 3, then |adj (A)| = ______
Find the inverse of matrix B = `[(3,1, 5),(2, 7, 8),(1, 2, 5)]` by using adjoint method
Find the inverse of the following matrix:
`[(3,1),(-1,3)]`
Find the inverse of the following matrix:
`[(1,2,3),(0,2,4),(0,0,5)]`
Solve by matrix inversion method:
2x + 3y – 5 = 0; x – 2y + 1 = 0.
Solve by matrix inversion method:
3x – y + 2z = 13; 2x + y – z = 3; x + 3y – 5z = - 8
Solve by matrix inversion method:
x – y + 2z = 3; 2x + z = 1; 3x + 2y + z = 4
The inverse matrix of `((3,1),(5,2))` is
The matrix A = `[("a",-1,4),(-3,0,1),(-1,1,2)]` is not invertible only if a = _______.
The sum of the cofactors of the elements of second row of the matrix `[(1, 3, 2), (-2, 0, 1), (5, 2, 1)]` is ____________.
If A = `[(1,-1,1),(2,1,-3),(1,1,1)]`, then the sum of the elements of A-1 is ______.
The matrix `[(lambda, 1, 0),(0, 3, 5),(0, -3, lambda)]` is invertible ______.
If the inverse of the matrix A = `[(1, 1, -1), (1, -2, 1), (2, -1, -3)]` is `1/9 [(7, 4, -1), (5, -1, -2), (3, 3, a)]`, then a is equal to ______
The inverse of the matrix A = `[(3, 0, 0),(0, 4, 0),(0, 0, 5)]` is ______.
If A = `[(2, -3, 3),(2, 2, 3),(3, "p", 2)]` and A–1 = `[(-2/5, 0, 3/5),(-1/5, 1/5, "q"),(2/5, 1/5, -2/5)]`, then ______.
If A = `[(1, 2, -1),(-1, 1, 2),(2, -1, 1)]`, then det (adj (adj A)) is ______.
If A = `[(1, 2, 3),(-1, 1, 2),(1, 2, 4)]` then (A2 – 5A)A–1 = ______.
If A = `[(2, 3),(4, 5)]`, show that A2 – 7A – 2I = 0