Advertisements
Advertisements
प्रश्न
Find the value of 'y' if `sqrt(3)` = 1.723.
Given your answer correct to 2 decimal places.
उत्तर
In right ΔPRS,
tan45° = `"PR"/"RS"`
⇒ 1 = `"PR"/(12)`
⇒ PR = 12
In right ΔQRS,
tan30° = `"QR"/"RS"`
⇒ `(1)/sqrt(3) = "QR"/(12)`
⇒ QR = `(12)/sqrt(3)`
Now,
y = PQ
= PR - QR
= `12 - (12)/sqrt(3)`
= `12 - (12)/(1.732)`
= 12 - 6.93
= 5.07.
APPEARS IN
संबंधित प्रश्न
If 4 cos2 x° - 1 = 0 and 0 ∠ x° ∠ 90°,
find:(i) x°
(ii) sin2 x° + cos2 x°
(iii) `(1)/(cos^2xx°) – (tan^2 xx°)`
Solve the following equation for A, if 2 sin 3 A = 1
If θ = 30°, verify that: 1 - sin 2θ = (sinθ - cosθ)2
If A = B = 60°, verify that: sin(A - B) = sinA cosB - cosA sinB
If `sqrt(3)` sec 2θ = 2 and θ< 90°, find the value of
cos 3θ
In a rectangle ABCD, AB = 20cm, ∠BAC = 60°, calculate side BC and diagonals AC and BD.
Find x and y, in each of the following figure:
If tan x° = `(5)/(12) . tan y° = (3)/(4)` and AB = 48m; find the length CD.
Evaluate the following: `(sin25° cos43°)/(sin47° cos 65°)`
If cos3θ = sin(θ - 34°), find the value of θ if 3θ is an acute angle.
