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प्रश्न
If m = `1/[ 3 - 2sqrt2 ] and n = 1/[ 3 + 2sqrt2 ],` find mn
योग
उत्तर
mn = ( 3 + 2√2 )( 3 - 2√2 ) = (3)2 - (2√2)2 = 9 - 8 = 1
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Rationalisation of Surds
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