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If sin 3A = 1 and 0 < A < 90°, find cos 2A - Mathematics

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प्रश्न

If sin 3A = 1 and 0 < A < 90°, find cos 2A

योग

उत्तर

sin 3A = 1 
sin 3A = sin90°
3A = 90°
A = 30°

cos 2A = cos 2(30°)
= cos 60°
= `(1)/(2)`

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Trigonometric Equation Problem and Solution
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 23: Trigonometrical Ratios of Standard Angles [Including Evaluation of an Expression Involving Trigonometric Ratios] - Exercise 23 (C) [पृष्ठ २९८]

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सेलिना Concise Mathematics [English] Class 9 ICSE
अध्याय 23 Trigonometrical Ratios of Standard Angles [Including Evaluation of an Expression Involving Trigonometric Ratios]
Exercise 23 (C) | Q 6.2 | पृष्ठ २९८
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