Advertisements
Advertisements
प्रश्न
If sin 3A = 1 and 0 < A < 90°, find sin A
उत्तर
sin 3A = 1
sin 3A = sin90°
3A = 90°
A = 30°
sin A = sin30°
sin A = `(1)/(2)`
APPEARS IN
संबंधित प्रश्न
Calculate the value of A, if cos 3A. (2 sin 2A - 1) = 0
If 3 tan A - 5 cos B = `sqrt3` and B = 90°, find the value of A
If A = B = 60°, verify that: tan(A - B) = `(tan"A" - tan"B")/(1 + tan"A" tan"B"")`
Find the length of AD. Given: ∠ABC = 60°, ∠DBC = 45° and BC = 24 cm.
Find lengths of diagonals AC and BD. Given AB = 24 cm and ∠BAD = 60°.
Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: sin53° + sec66° - sin50°
If sin(θ - 15°) = cos(θ - 25°), find the value of θ if (θ-15°) and (θ - 25°) are acute angles.
If secθ= cosec30° and θ is an acute angle, find the value of 4 sin2θ - 2 cos2θ.
Prove the following: sin230° + cos230° = `(1)/(2)sec60°`
If A + B = 90°, prove that `(tan"A" tan"B" + tan"A" cot"B")/(sin"A" sec"B") - (sin^2"B")/(cos^2"A")` = tan2A