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In Each of the Following, Find the Value of the Constant K So that the Given Function is Continuous at the Indicated Point; F ( X ) = { K ( X 2 + 2 ) , If X ≤ 0 3 X + 1 , If X > 0 - Mathematics

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प्रश्न

In each of the following, find the value of the constant k so that the given function is continuous at the indicated point; \[f\left( x \right) = \begin{cases}k( x^2 + 2), \text{if} & x \leq 0 \\ 3x + 1 , \text{if} & x > 0\end{cases}\]

योग

उत्तर

\[f\left( x \right) = \begin{cases}k( x^2 + 2), \text{if} & x \leq 0 \\ 3x + 1 , \text{if} & x > 0\end{cases}\]

 We have
(LHL at x = 0) = 

\[\lim_{x \to 0^-} f\left( x \right) = \lim_{h \to 0} f\left( 0 - h \right) = \lim_{h \to 0} k\left( \left( - h \right)^2 + 2 \right) = 2k\]
(RHL at x = 0) = 
\[\lim_{x \to 0^+} f\left( x \right) = \lim_{h \to 0} f\left( 0 + h \right) = \lim_{h \to 0} 3h + 1 = 1\]
If f(x) is continuous at x = 0, then
\[\lim_{x \to 0^-} f\left( x \right) = \lim_{x \to 0^+} f\left( x \right)\]
\[ \Rightarrow 2k = 1\]
\[ \Rightarrow k = \frac{1}{2}\]
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अध्याय 9: Continuity - Exercise 9.1 [पृष्ठ २०]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 9 Continuity
Exercise 9.1 | Q 36.8 | पृष्ठ २०

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