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प्रश्न
In the given figure PA = 10, PB = 2 and PC = 5. Find PD.
उत्तर
We know that when two chords intersect each other inside a circle, the product of thier segments are equal.
The chords AB and CD intersect at P, so
PA × PB = PC × PD
\[\Rightarrow 10 \times 2 = 5 \times PD\]
\[ \Rightarrow PD = \frac{10 \times 2}{5} = 4\]
Thus, PD = 4 units.
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