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प्रश्न
Prove the following:
sin 20° sin 40° sin 80° = `sqrt(3)/8`
उत्तर
L.H.S. = sin 20° sin 40° sin 80°
= sin 20°. sin 40°. sin 80°
= `1/2(2.sin40^circ.sin20^circ).sin80^circ`
= `1/2[cos(40^circ - 20^circ) - cos(40^circ + 20^circ)].sin80^circ`
= `1/2(cos20^circ - cos60^circ)sin80^circ`
= `1/2cos20^circ.sin80^circ - 1/2 cos60^circ.sin80^circ`
= `1/(2 xx 2)(2sin80^circ.cos20^circ) - 1/2(1/2).sin80^circ`
= `1/4.[sin(80^circ + 20^circ) + sin(80^circ - 20^circ)] - 1/4.sin80^circ`
= `1/4.(sin100^circ + sin60^circ) - 1/4.sin80^circ`
= `1/4sin 100^circ + 1/4sin 60^circ - 1/4sin 80^circ`
= `1/4.sin(180^circ - 80^circ) + 1/4 xx sqrt(3)/2 - 1/4.sin80^circ`
= `1/4sin80^circ + sqrt(3)/8 - 1/4sin80^circ` ...[∵ sin (180° – θ) = sin θ]
= `sqrt(3)/8`
= R.H.S.
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