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प्रश्न
Show that the points A(1, 2), B(– 1, – 16) and C(0, – 7) lie on the graph of the linear equation y = 9x – 7.
उत्तर
Firstly, to draw the graph of equation y = 9x – 7
When x = 2, then y = 9 × 2 – 7
= 18 – 7
= 11
When x = – 2, then y = 9 × – 2 – 7
= – 18 – 7
= – 25
| x | 2 | – 2 |
| y | 11 | – 25 |
Here, we find two points D(2, 11) and E(–2, – 25).
So, draw the graph by plotting the points and joining the line DE.
Now, we plot the given points A(1, 2), B(–1, –16) and C(0, –7) on the graph paper. We see that all the points lie on DE line.
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