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Show with the usual notation that for any matrix A = aijisaAaAaA[aij]3×3 is a11A21+a12A22+a13A23=0 - Mathematics and Statistics

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प्रश्न

Show with the usual notation that for any matrix A = `["a"_"ij"]_(3xx3)  "is"   "a"_11"A"_21 + "a"_12"A"_22 + "a"_13"A"_23 = 0` 

योग

उत्तर

A = `["a"_"ij"]_(3xx3) = [("a"_11,"a"_12,"a"_13),("a"_21,"a"_22,"a"_23),("a"_31,"a"_32,"a"_33)]`

`"A"_21 = (-1)^(2+1)"M"_21 = - |("a"_12,"a"_13),("a"_32,"a"_33)|`

`= - ("a"_12"a"_33 - "a"_13"a"_32)`

`= - "a"_12"a"_33 + "a"_13"a"_32`

`"A"_22 = (-1)^(2+2)"M"_22 = - |("a"_11,"a"_13),("a"_31,"a"_33)|`

= a11a33 - a13a31

`"A"_23 = (-1)^(2+3)"M"_23 = - |("a"_11,"a"_12),("a"_31,"a"_32)|`

= - (a11a32 - a12a31)

= - a11a32 + a12a31

∴ `"a"_11"A"_21 + "a"_12"A"_22 + "a"_13"A"_23`

`= "a"_11 (- "a"_12"a"_33 + "a"_13"a"_32) + "a"_12("a"_11"a"_33 - "a"_13"a"_31) + "a"_13(- "a"_11"a"_32 + "a"_12"a"_31)`

`= - "a"_11"a"_12"a"_33 + "a"_11"a"_13"a"_32 + "a"_11"a"_12"a"_33 - "a"_12"a"_13"a"_31 - "a"_11"a"_13"a"_32 + "a"_12"a"_13"a"_31`

= 0

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Elementry Transformations
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Matrics - Miscellaneous exercise 2 (A) [पृष्ठ ५४]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] 12 Standard HSC Maharashtra State Board
अध्याय 2 Matrics
Miscellaneous exercise 2 (A) | Q 19.1 | पृष्ठ ५४

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