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प्रश्न
∆ABC is an isosceles triangle in which ∠C = 90. If AC = 6 cm, then AB =
पर्याय
- \[6\sqrt{2} cm\]
6 cm
- \[2\sqrt{6} cm\]
- \[4\sqrt{2} cm\]
उत्तर
Given: In an isosceles ΔABC, `∠C= 90^o`, AC = 6 cm.
To find: AB
In an isosceles ΔABC, `∠C= 90^o`,.
Therefore, BC = AC = 6 cm
Applying Pythagoras theorem in ΔABC, we get
`AB^2=AC^2+BC^2`
`AB^2=6^2+6^2(AC=BC)`(Side of isosceles triangle)
`AB^2=36+36`
`AB^2=72`
`AB= 6sqrt2 cm`
We got the result as `a`.
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