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प्रश्न
Evaluate:
`int (1 + cosx)/(sin^2x)dx`
उत्तर
`int (1 + cosx)/(sin^2x)dx`
= `int (1/(sin^2x) + cosx/(sin^2x))dx`
= `int ("cosec"^2x + cot x "cosec" x)dx`
= `int "cosec"^2x dx + int cot x "cosec" x dx`
= – cot x – cosec x + C.
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