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Evaluate: ∫1+cosxsin2xdx - Mathematics

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प्रश्न

Evaluate:

`int (1 + cosx)/(sin^2x)dx`

योग

उत्तर

`int (1 + cosx)/(sin^2x)dx`

= `int (1/(sin^2x) + cosx/(sin^2x))dx`

= `int ("cosec"^2x + cot x  "cosec"  x)dx`

=  `int "cosec"^2x  dx + int cot x  "cosec"  x  dx`

= – cot x – cosec x + C.

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Evaluation of Definite Integrals by Substitution
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
Q 1.xiv
2022-2023 (March) Official

APPEARS IN

2022-2023 (March) Official (with solutions)
Q 1.xiv | 1 mark

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