Advertisements
Advertisements
प्रश्न
Evaluate of the following:
(9.9)3
उत्तर
In the given problem, we have to find the value of numbers
Given (9.9)3
In order to find (9.9)3 we are using identity `(a-b)^3 = a^3 - b^3 - 3ab(a-b)`
We can write (9.9)3 as `(10-0.1)^3`
Hence where a = 10,b = 0.1
`(9.9)^3 = (10 - 0.1)^3`
` = (10)^3 - (0.1)^3 - 3(10)(0.1)(10 - 0.1)`
` = 1000 - 0.001 - 3 xx 9.9`
` = 1000 - 0.001 - 29.7`
` = 1000 - 29.701`
` = 970.299`
The value of (9.9)3 is 970.299.
APPEARS IN
संबंधित प्रश्न
Write the following cube in expanded form:
`[3/2x+1]^3`
Factorise the following:
`27p^3-1/216-9/2p^2+1/4p`
Factorise the following:
27y3 + 125z3
Without actually calculating the cubes, find the value of the following:
(28)3 + (–15)3 + (–13)3
Evaluate the following using identities:
(0.98)2
Simplify the following:
0.76 x 0.76 - 2 x 0.76 x 0.24 x 0.24 + 0.24
Write in the expanded form:
(2a - 3b - c)2
If a + b + c = 9 and ab + bc + ca = 23, find the value of a2 + b2 + c2.
Simplify of the following:
(2x − 5y)3 − (2x + 5y)3
Find the following product:
If a + b + c = 9 and ab +bc + ca = 26, find the value of a3 + b3+ c3 − 3abc
If \[x - \frac{1}{x} = \frac{1}{2}\],then write the value of \[4 x^2 + \frac{4}{x^2}\]
(a − b)3 + (b − c)3 + (c − a)3 =
Use identities to evaluate : (97)2
Evaluate: `(3"x"+1/2)(2"x"+1/3)`
Evaluate: (2a + 0.5) (7a − 0.3)
Evaluate: `(4/7"a"+3/4"b")(4/7"a"-3/4"b")`
Find the squares of the following:
(2a + 3b - 4c)
Factorise the following:
9x2 + 4y2 + 16z2 + 12xy – 16yz – 24xz
Expand the following:
`(4 - 1/(3x))^3`
