Advertisements
Advertisements
प्रश्न
Find:-
`64^(1/2)`
उत्तर
We can write the given expression as follows
⇒ `64^(1/2) = (8^2)^(1/2)`
On simplifying it
⇒ `64^(1/2) = 8^(2 xx 1/2)`
∴ `64^(1/2) = 8`
APPEARS IN
संबंधित प्रश्न
Simplify the following
`((4xx10^7)(6xx10^-5))/(8xx10^4)`
Given `4725=3^a5^b7^c,` find
(i) the integral values of a, b and c
(ii) the value of `2^-a3^b7^c`
Assuming that x, y, z are positive real numbers, simplify the following:
`(sqrtx)^((-2)/3)sqrt(y^4)divsqrt(xy^((-1)/2))`
Prove that:
`sqrt(1/4)+(0.01)^(-1/2)-(27)^(2/3)=3/2`
Find the value of x in the following:
`(13)^(sqrtx)=4^4-3^4-6`
If `3^(x+1)=9^(x-2),` find the value of `2^(1+x)`
If `a=x^(m+n)y^l, b=x^(n+l)y^m` and `c=x^(l+m)y^n,` Prove that `a^(m-n)b^(n-l)c^(l-m)=1`
The product of the square root of x with the cube root of x is
Which one of the following is not equal to \[\left( \frac{100}{9} \right)^{- 3/2}\]?
Simplify:
`(9^(1/3) xx 27^(-1/2))/(3^(1/6) xx 3^(- 2/3))`