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प्रश्न
Find `dy/dx` if y = x2 + 2x – 1
उत्तर
y = x2 + 2x – 1
Differentiating w.r.t. x, we get
`dy/dx=d/dx(x^2+2^x-1)`
=`d/dx(x^2)+d/dx(2^x)-d/dx(1)`
= 2x + 2x log 2 – 0
= 2x + 2x log 2
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