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Find the Interval in Which the Following Function Are Increasing Or Decreasing F(X) = 5x3 − 15x2 − 120x + 3 ? - Mathematics

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प्रश्न

Find the interval in which the following function are increasing or decreasing  f(x) = 5x3 − 15x2 − 120x + 3 ?

बेरीज

उत्तर

\[\text { When } \left( x - a \right)\left( x - b \right)>0 \text { with }a < b, x < a \text { or }x>b.\]

\[\text { When } \left( x - a \right)\left( x - b \right)<0 \text { with } a < b, a < x < b .\]

\[f\left( x \right) = 5 x^3 - 15 x^2 - 120x + 3\]

\[f'\left( x \right) = 15 x^2 - 30x - 120\]

\[ = 15 \left( x^2 - 2x - 8 \right)\]

\[ = 15 \left( x - 4 \right)\left( x + 2 \right)\]

\[\text { For }f(x) \text { to be increasing, we must have }\]

\[f'\left( x \right) > 0\]

\[ \Rightarrow 15 \left( x - 4 \right)\left( x + 2 \right) > 0 \]

\[ \Rightarrow \left( x - 4 \right)\left( x + 2 \right) > 0 \left[ \text { Since } 15 > 0, 15 \left( x - 4 \right)\left( x + 2 \right) > 0 \Rightarrow \left( x - 4 \right)\left( x + 2 \right) > 0 \right]\]

\[ \Rightarrow\text{ x }< - 2 \ or \ x > 4\]

\[ \Rightarrow x \in \left( - \infty , - 2 \right) \cup \left( 4, \infty \right)\]

\[\text { So },f(x)\text { is increasing on x } \in \left( - \infty , - 2 \right) \cup \left( 4, \infty \right).\]

\[\text { For }f(x) \text { to be decreasing, we must have },\]

\[f'\left( x \right) < 0\]

\[ \Rightarrow 15 \left( x - 4 \right)\left( x + 2 \right) < 0\]

\[ \Rightarrow \left( x - 4 \right)\left( x + 2 \right) < 0 \left[ \text { Since } 15 > 0, 15 \left( x - 4 \right)\left( x + 2 \right) < 0 \Rightarrow \left( x - 4 \right)\left( x + 2 \right) < 0 \right]\]

\[ \Rightarrow - 2 < x < 4\]

\[ \Rightarrow x \in \left( - 2, 4 \right)\]

\[\text { So, }f(x)\text { is decreasing on } x \in \left( - 2, 4 \right) .\]

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पाठ 17: Increasing and Decreasing Functions - Exercise 17.2 [पृष्ठ ३३]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 17 Increasing and Decreasing Functions
Exercise 17.2 | Q 1.07 | पृष्ठ ३३

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