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प्रश्न
Find the value of `sec(tan^-1 y/2)`
उत्तर
Let `tan^-1 y/2` = θ
Where `theta ∈ (- pi/2, pi/2)`
So tan θ = `y/2`
Which gives sec θ = `sqrt(4 + y^2)/2`
Therefore, `sec(tan^-1 y/2)` = sec θ = `sqrt(4 + y^2)/2`.
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