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प्रश्न
If sinA = `(3)/(5)`, find cosA and tanA.
उत्तर
sinA = `(3)/(5) = "Perpendicular"/"Hypotenuse"`
By Pythagoras theorem, we have
⇒ (Hypotenuse)2 = (Perpendicular)2 + (Base)2
⇒ (Base)2 = (Hypotenuse)2 - (Perpendicular)2
⇒ (Base) = `sqrt(("Hypotenuse")^2 - ("Perpendicular")^2`
⇒ (Base)
= `sqrt(5^2 - 3^2)`
= `sqrt(25 - 9)`
= `sqrt(16)`
= 4
cos A = `"Base"/"Hypotenuse" = (4)/(5)`
tan A = `"Perpendicular"/"Base" = (3)/(4)`.
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