Advertisements
Advertisements
प्रश्न
If (x − 1)3 = 8, What is the value of (x + 1)2 ?
उत्तर
We have to find the value of , `(x+1)^2`where `(x-1)^3 = 8`
Consider `(x-1)^3 =2^3`
By equating the base, we get
x-1 = 2
x=2+1
x = 3
By substituting x = 3in `(x+1)^2`
`= (x+1)^2`
`=(3+1)^2`
`=4^2`
`= 4 xx 4 `
=1 6
Hence the value of `(x+1)^2` is 16.
APPEARS IN
संबंधित प्रश्न
Simplify the following
`((x^2y^2)/(a^2b^3))^n`
Solve the following equation for x:
`2^(3x-7)=256`
If 2x = 3y = 12z, show that `1/z=1/y+2/x`
Solve the following equation:
`4^(x-1)xx(0.5)^(3-2x)=(1/8)^x`
State the product law of exponents.
Which of the following is (are) not equal to \[\left\{ \left( \frac{5}{6} \right)^{1/5} \right\}^{- 1/6}\] ?
When simplified \[( x^{- 1} + y^{- 1} )^{- 1}\] is equal to
If x-2 = 64, then x1/3+x0 =
(256)0.16 × (256)0.09
The simplest rationalising factor of \[\sqrt[3]{500}\] is
