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प्रश्न
In the following figure, Prove that AD is parallel to FE.
उत्तर
Now, ∠BAD + ∠BFE
= 96 °+ 84°
= 180°
But these two are interior angles on the same side of a pair of lines AD and FE
∴ AD || FE
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`square` is the exterior angle of ABCD
To prove: ∠DCE ≅ ∠BAD
Proof: `square` + ∠BCD = `square` .....[Angles in linear pair] (I)
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`square` + ∠BAD = `square` ......[Theorem of cyclic quadrilateral] (II)
By (I) and (II)
∠DCE + ∠BCD = `square` + ∠BAD
∠DCE ≅ ∠BAD
