Advertisements
Advertisements
Question
In the following figure, Prove that AD is parallel to FE.
Solution
Now, ∠BAD + ∠BFE
= 96 °+ 84°
= 180°
But these two are interior angles on the same side of a pair of lines AD and FE
∴ AD || FE
APPEARS IN
RELATED QUESTIONS
In the following figure,
- if ∠BAD = 96°, find ∠BCD and ∠BFE.
- Prove that AD is parallel to FE.
In a cyclic quadrilateral ABCD, ∠A : ∠C = 3 : 1 and ∠B : ∠D = 1 : 5; find each angle of the quadrilateral.
D and E are points on equal sides AB and AC of an isosceles triangle ABC such that AD = AE. Prove that the points B, C, E and D are concyclic.
In the following figure, ABCD is a cyclic quadrilateral in which AD is parallel to BC.
If the bisector of angle A meets BC at point E and the given circle at point F, prove that:
- EF = FC
- BF = DF
In a circle with centre O , chords AB and CD intersets inside the circle at E . Prove that ∠ AOC = ∠ BOD = 2 ∠ AEC.
In fig., O is the centre of the circle and ∠ AOC = 1500. Find ∠ ABC.
ABCDE is a cyclic pentagon with centre of its circumcircle at point O such that AB = BC = CD and angle ABC=120°.
Calculate: ∠ BED.
In the figure, given below, find: ∠ADC, Show steps of your working.
In the figure , Δ PQR is an isosceles triangle with PQ = PR, and m ∠ PQR = 35°. Find m ∠ QSR and ∠ QTR.
In the figure alongside PR is a diameter of the circle, PQ = 7 cm; QR = 6 cm and RS = 2 cm. Calculate the perimeter of the cyclic quadrilateral PQRS.