मराठी

In the Given Figure, Abc is a Triangle and Ad is the Median.If E is Any Point on the Median Ad. Show That: Area of δAbe = Area of δAce. - Mathematics

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प्रश्न

In the given figure, ABC is a triangle and AD is the median.

If E is any point on the median AD. Show that: Area of ΔABE = Area of ΔACE.

बेरीज

उत्तर

AD is the median of ΔABC.
Therefore it will divide ΔABC into two triangles of equal areas.
∴ Area(ΔABD) = Area(ΔACD) ….(i)
Similarly, ED is the median of ΔEBC.
∴ Area(DEBD) = Area(DECD) ….(ii)
Subtracting equation (ii) from (i), we have
Area(ΔABD) - Area(ΔEBD) = Area(ΔACD) - Area(ΔECD) 
⇒ Area(ΔABE) = Area(ΔACE).

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पाठ 21: Areas Theorems on Parallelograms - Exercise 21.1

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फ्रँक Mathematics [English] Class 9 ICSE
पाठ 21 Areas Theorems on Parallelograms
Exercise 21.1 | Q 34.1

संबंधित प्रश्‍न

ABCD is a trapezium in which AB || CD and AD = BC (see the given figure). Show that

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  2. ∠C = ∠D
  3. ΔABC ≅ ΔBAD
  4. diagonal AC = diagonal BD

[Hint: Extend AB and draw a line through C parallel to DA intersecting AB produced at E.]


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