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प्रश्न
Show that:
`((a+1/b)^mxx(a-1/b)^n)/((b+1/a)^mxx(b-1/a)^n)=(a/b)^(m+n)`
उत्तर
`((a+1/b)^mxx(a-1/b)^n)/((b+1/a)^mxx(b-1/a)^n)=(a/b)^(m+n)`
`=(((ab+1)/b)^mxx((ab-1)/b)^n)/(((ab+1)/a)^mxx((ab-1)/a)^n)`
`=(((ab+1)/b)/((ab+1)/a))^mxx(((ab-1)/b)/((ab-1)/a))^n`
`=((ab+1)/bxxa/(ab+1))^mxx((ab-1)/bxxa/(ab-1))^n`
`=(a/b)^mxx(a/b)^n`
`=(a/b)^(m+n)`
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