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प्रश्न
Solve for x:
5tan–1x + 3cot–1x = 2π
उत्तर
5tan–1x + 3cot–1x = 2π
`\implies 5tan^-1x + 3(π/2 - tan^-1x)` = 2π
`\implies` 5tan–1x – 3tan–1x = `2π - (3π)/2`
2tan–1x = `π/2`
tan–1x = `π/4`
x = `tan π/4`
= 1
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