मराठी

The differential equation of the family of curves x2 + y2 – 2ay = 0, where a is arbitrary constant, is ______. - Mathematics

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प्रश्न

The differential equation of the family of curves x2 + y2 – 2ay = 0, where a is arbitrary constant, is ______.

पर्याय

  • `(x^2 - y^2) ("d"y)/("d"x)` = 2xy

  • `2(x^2 + y^2) ("d"y)/("d"x)` = xy

  • `2(x^2 - y^2) ("d"y)/("d"x)` = xy

  • `(x^2 + y^2) ("d"y)/("d"x)` = 2xy

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उत्तर

The differential equation of the family of curves x2 + y2 – 2ay = 0, where a is arbitrary constant, is `(x^2 - y^2) ("d"y)/("d"x)` = 2xy.

Explanation:

The given equation is x2 + y2 – 2ay = 0   ......(1)

Differentiating w.r.t. x, we have

`2x + 2y * ("d"y)/("d"x) - 2"a" ("d"y)/("d"x)` = 0

⇒ `x + y ("d"y)/("d"x) - "a" ("d"y)/("d"x)` = 0

⇒ `x + (y - "a") ("d"y)/("d"x)` = 0

⇒ `(y - "a") ("d"y)/("d"x)` = – x

⇒ y – a = `(-x)/(("d"y)/("d"x))`

⇒ a = `y + x/(("d"y)/("d"x))`

⇒ a = `(y * ("d"y)/("d"x) + x)/(("d"y)/("d"x))`

Putting the value of a in equation (1) we get

`x^2 + y^2 - 2y [(y ("d"y)/("d"x) + x)/(("d"y)/("d"x))]` = 0

⇒ `(x^2 + y^2) ("d"y)/("d"x) - 2y(y ("d"y)/("d"x) + x)` = 0

⇒ `(x^2 + y^2) ("d"y)/("d"x) - 2y^2 ("d"y)/("d"x) - 2xy` = 0

⇒ `(x^2 + y^2 - 2y^2) ("d"y)/("d"x^2)` = 2xy

⇒ `(x^2 - y^2) ("d"y)/("d"x)` = 2xy

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पाठ 9: Differential Equations - Exercise [पृष्ठ १९९]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
पाठ 9 Differential Equations
Exercise | Q 59 | पृष्ठ १९९

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