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प्रश्न
Represent the following families of curves by forming the corresponding differential equations (a, b being parameters):
x2 + (y − b)2 = 1
उत्तर
The equation of family of curves is \[x^2 + \left( y - b \right)^2 = 1.........(1)\]
where `b` is a parameter.
As this equation contains only one arbitrary constant, we shall get a differential equation of first order.
Differentiating (1) with respect to x, we get
\[2x + 2\left( y - b \right)\frac{dy}{dx} = 0\]
\[ \Rightarrow 2x + 2\sqrt{1 - x^2}\frac{dy}{dx} = 0 .......\left[ \text{Using }\left( 1 \right) \right]\]
\[ \Rightarrow x = - \sqrt{1 - x^2}\frac{dy}{dx}\]
\[ \Rightarrow x^2 = \left( 1 - x^2 \right) \left( \frac{dy}{dx} \right)^2 \]
\[ \Rightarrow x^2 = \left( \frac{dy}{dx} \right)^2 - x^2 \left( \frac{dy}{dx} \right)^2 \]
\[ \Rightarrow x^2 \left[ 1 + \left( \frac{dy}{dx} \right)^2 \right] = \left( \frac{dy}{dx} \right)^2 \]
It is the required differential equation.
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